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Joseph jogs from one end A to other end B of a straight $300 m$ road in $2 \min 30 s$ and then turns around and jogs $100 m$ back to point C in another $1 \min$ . The average speed of Joseph while jogging from A to B is $m / s$ and from B to A is $m / s$ .

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Detailed Solution

Joseph jogs from one end A to other end B of a straight

300 m

road in

2 \min 30 s

and then turns around and jogs

100 m

back to point C in another

1 \min

. The average speed of Joseph while jogging from A to B is

2 m / s

and from B to A is

0.952 m / s

Average velocity is defined as the ratio of total displacement to the total time taken.
The displacement for moving from A to B is

300 m

and total time taken is,

= 2 \times 60 + 30

= 120 + 30

= 150 s

Average velocity will be,

average velocity = \frac{300}{150}

= 2 m / s

When Joseph returns

100 m

then the total displacement becomes,

300 - 100 = 200 m

But the time taken increases to

3 \min 30 s

which is equal to,

3 \times 60 + 30 = 180 + 30

= 210 s

The average velocity will be equal to,

average velocity = \frac{200}{210}

= 0.952 m / s

The average velocity of Joseph for jogging from A to B is

2 m / s

and for jogging from B to A is

0.952 m / s

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