Joseph jogs from one end A to other end B of a straight $300\mathit{ m}$ road in $2\mathit{ min }30\mathit{ s}$ and then turns around and jogs $100\mathit{ m}$ back to point C in another $1\mathit{ min}$. The average speed of Joseph while jogging from A to B is ____$\mathit{ m}/s$ and from B to A is ____ $m/s$.

Joseph jogs from one end A to other end B of a straight $300\mathit{ m}$ road in $2\mathit{ min }30\mathit{ s}$ and then turns around and jogs $100\mathit{ m}$ back to point C in another $1\mathit{ min}$. The average speed of Joseph while jogging from A to B is $2\mathit{ m}/s$ and from B to A is $0.952\mathit{ m}/s$.
 Average velocity is defined as the ratio of total displacement to the total time taken.
The displacement for moving from A to B is $300\mathit{ m}$ and total time taken is, 
$=2\times 60+30$
$=120+30$
$=150\mathit{ s}$
Average velocity will be,
$\mathit{average\; velocity}=\frac{300}{150}$
                                $=2\mathit{ m}/s$
When Joseph returns $100m$ then the total displacement becomes,
$300-100=200\mathit{ m}$
But the time taken increases to $3\mathit{min}30s$ which is equal to,
$3\times 60+30=180+30$
                         $=210\mathit{ s}$
The average velocity will be equal to,
$\mathit{average\; velocity}=\frac{200}{210}$
                                $=0.952\mathit{ m}/s$
The average velocity of Joseph for jogging from A to B is $2\mathit{ m}/s$ and for jogging from B to A is $0.952\mathit{ m}/s$.