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$K_{2} {Cr}_{2} O_{7} + H_{2} {SO}_{4} + 4 H_{2} O_{2} \to \underset{Sulphur compound}{X} + \underset{Chromium compound}{Y} + 5 H_{2} O$
In above reaction identify the oxidation state of chromium in compound $' Y'$ .

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$+ 10$

$+ 6$

$+ 8$

$+ 7$

answer is C.

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Detailed Solution

$Compound Y is {CrO}_{5} Butterfly structure$

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