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$K_{2} M n O_{4}$ In acidic medium, it changes from green to purple after some time. This change is accompanied by

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Formation of tetrahedral oxoanion of Mn with oxidation state +7

Disproportionation of $K_{2} M n O_{4}$

Separation of the brown or black mass from the solution

Decrease in pH of solution

answer is A, C, D.

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Detailed Solution

$3 K_{2} M n O_{4} + 4 H' ⇌ \underset{(p u r p l e)}{2 K M n O_{4}} + \underset{(b r o w n)}{M n O_{2} ↓} + 2 H_{2} O$

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