$\begin{aligned} K_{6} [(CN)_{5} Co - O - O - Co (CN)_{5}] \overset{oxidizes}{⟶} K_{5} [(CN)_{5} Co - O - O - Co (CN)_{5}] \end{aligned}$
(X) (Y)
In both the complexes Co have ${^{t}}_{g}^{6} {e_{g}}^{0}$ configuration. The bond energy of ( $O - O$ ) in X and Y is :

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bond energy of( $O - O$ ) in X and bond energy of ( $O - O$ ) in Y can't be comparable.

bond energy of ( $O - O$ ) in X = bond energy of ( $O - O$ ) in Y.

bond energy of ( $O - O$ ) in X < bond energy of ( $O - O$ ) in Y.

bond energy of ( $O - O$ ) in Y < bond energy of ( $O - O$ ) ln X.

answer is B.

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Detailed Solution

Since $O_{2}^{2 -}$ which is diamagnetic and having bond order 1 is converted into the $O_{2}^{-}$ having paramagnetic nature and bond order 1.5 , the bond energy of ( $O - O$ ) in X is grater than the bond energy of ( $O - O$ ) in Because bond energy is increases with the bond order.