Ka Values of 5 weak acids are given as HA=10−8 .HB=10−6 . HC=2×10−8 HD=10−10HE=10−7 Select the correct statement /s as per information (log2=0.3010,Kw=10−14)

Kn=KwKaHigher the value of Kn , more extensively hydrolyzed PH=7+12Pka+12 logcIsohydric solution PHEH=PHBH

Ka Values of 5 weak acids are given as HA=10−8 .HB=10−6 . HC=2×10−8 HD=10−10HE=10−7 Select the correct statement /s as per information (log2=0.3010,Kw=10−14)

Kn=KwKaHigher the value of Kn , more extensively hydrolyzed PH=7+12Pka+12 logcIsohydric solution PHEH=PHBH

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$K_{a}$ Values of 5 weak acids are given as $H A = 10^{- 8}$ . $H B = 10^{- 6}$ . $H C = 2 \times 10^{- 8} H D = 10^{- 10}$ $H E = 10^{- 7}$ Select the correct statement /s as per information $(\log 2 = 0.3010, K_{w} = 10^{- 14})$

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Among NaA, NaB, NaC, NaD & NaE the NaD is most extensively hydrolyzed

Among NaA, NaB, NaC, NaD & NaE the NaB is most extensively hydrolyzed

pH of 0.1M aq solution of NaB is approximately 9.5

0.1M solution of HE & 0.01M solution of HB are isohydric to each other approximately

answer is A, D, C.

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Detailed Solution

$K_{n} = \frac{K_{w}}{K_{a}}$
Higher the value of $K_{n}$ , more extensively hydrolyzed
$P^{H} = 7 + \frac{1}{2} P^{k_{a}} + \frac{1}{2} \log c$
Isohydric solution $P_{H E}^{H} = P_{H B}^{H}$

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Ka Values of 5 weak acids are given as HA=10−8 .HB=10−6 . HC=2×10−8 HD=10−10HE=10−7 Select the correct statement /s as per information (log2=0.3010,Kw=10−14)

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$K_{a}$ Values of 5 weak acids are given as $H A = 10^{- 8}$ . $H B = 10^{- 6}$ . $H C = 2 \times 10^{- 8} H D = 10^{- 10}$ $H E = 10^{- 7}$ Select the correct statement /s as per information $(\log 2 = 0.3010, K_{w} = 10^{- 14})$