Ka₁, Ka₂ and Ka₃ are the respective ionization constants for the following reactions (a),(b), and (c).
(a) $H_{2} C_{2} O_{4} ⇌ H^{+} + {HC}_{2} O_{4}^{-}$
(b) ${HC}_{2} O_{4}^{-} ⇌ H^{+} + {HC}_{2} O_{4}^{2 -}$
(c) $H_{2} C_{2} O_{4} ⇌ 2 H^{+} + C_{2} O_{4}^{2 -}$
The relationship between $K_{a_{1}}, K_{a_{2}} and K_{a_{3}}$ is given as

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$K_{a_{3}} = K_{a_{1}} / K_{a_{2}}$

$K_{a_{3}} = K_{a_{1}} + K_{a_{2}}$

$K_{a_{3}} = K_{a_{1}} \times K_{a_{2}}$

$K_{a_{3}} = K_{a_{1}} - K_{a_{2}}$

answer is D.

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Detailed Solution

$\begin{array}{l} H_{2} C_{2} O_{4} ⇌ H^{+} + {HC}_{2} O_{4}^{-} K_{a_{1}} \\ H_{2} C_{2} O_{4}^{-} ⇌ H^{+} + C_{2} O_{4}^{2 -} K_{a_{2}} \\ H_{2} C_{2} O_{4} ⇌ 2 H^{+} + C_{2} O_{4}^{2 -} K_{a_{3}} = K_{a_{1}} \times K_{a_{2}} \end{array}$

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