Karl Pearson’s coefficient of skewness of a distribution is 0.32, its S.D is 6.5 and mean is 29.6. The mode and median of the distribution are

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27.52, 28.91

26.92, 27.23

25.67, 26.34

None of these

answer is A.

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Detailed Solution

Given that Korl Pearson’s coefficient of skewness of a distribution 3.2
S.D = 6.5
Mean = 29.6
Formula used
1. skewness =

2. skewness =

On putting values in formula 1

mode
Mode = 29.6 − 2.08
Mode = 27.52
On putting values in formula 2

Median = 29.6 − 0.69
Median = 28.91
Hence, mode = 27.52, median = 28.91

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