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Q.

Karl Pearson’s coefficient of skewness of a distribution is 0.32, its S.D is 6.5 and mean is 29.6. The mode and median of the distribution are    

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a

27.52, 28.91

b

26.92, 27.23

c

25.67, 26.34

d

None of these 

answer is A.

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Detailed Solution

 Given that Korl Pearson’s coefficient of skewness of a distribution 3.2
S.D = 6.5
Mean = 29.6
Formula used
1. skewness = Question Image2. skewness = Question ImageOn putting values in formula 1
Question ImageQuestion ImageQuestion Imagemode
Mode = 29.6 − 2.08
Mode = 27.52
On putting values in formula 2
Question ImageQuestion ImageQuestion ImageQuestion ImageMedian = 29.6 − 0.69
Median = 28.91
Hence, mode = 27.52,       median = 28.91
  
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