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Q.

${KCIO}_{3}$ decomposes to KCI and $O_{2} . If the volume of O_{2}$ obtained in this reaction is 1.12 lit at STP, weight of KCI formed in the reaction is

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a

7.45 grams

b

4.96 grams

c

1.24 g

d

2.48 grams

answer is B.

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Detailed Solution

$2 {KClO}_{3} \to 2 KCl + 3 O_{2}$

3 mole $O_{2} = 2 mole KCl$

1 mole $O_{2} = \frac{2}{3} mol . Kcl$

$22.4 {LtO}_{2} = \frac{2}{3} \times 74.6 grams$

11.2 Lt $O_{2} = \frac{1}{3} \times 74.6 grams = 24.8 grams$

$1.12 Lt of O_{2} = 2.48 grams$

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