Keeping the banking angle same, to increase the maximum speed with which a vehicle can travel on the curved road by 10%, the radius of curvature of the road has to be changed from 20 m to

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30.'5 m

16 m

18 m

24.2m

answer is C.

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Detailed Solution

Here banking angle and g are same, hence

$\begin{array}{l} \frac{V^{2}}{r} = constant \\ ∴ \frac{V_{1}^{2}}{V_{2}^{2}} = \frac{r_{1}}{r_{2}} or r_{2} = r_{1} \times \frac{v_{2}^{2}}{v_{1}^{2}} \\ or r_{2} = 20 \times \frac{{(110 / 100 \times v_{1})}^{2}}{v_{1}^{2}} \\ = 20 \times \frac{121}{100} = 24 \cdot 2 m \end{array}$

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