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Key is in position 2 for time $t_{0} .$ There after it is shifted to position 1. Resistance of the bulbs and inductance of the inductor are marked in the figure. Choose the correct alternative

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Total heat produced by bulb 1 is $\frac{L ε^{2}}{2 R_{2}^{2}}$

Bulb 2 dies as soon as the switch is shifted to position 1

Total heat produced by bulb 1 is $\frac{L ε^{2}}{2 R_{1}^{2}}$

Time in which brightness of bulb 1 becomes half of its maximum brightness does not depend on $t_{0}$

answer is A, B.

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Detailed Solution

After the switch is shifted to position 1, bulb, 2 dies at once while decay of current take place in inductor through bulb 1 . Bulb 1 dissipate all the energy stored in the inductor

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