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Q.

$K_{f}$ for water is 1.86 K. kg/mole. If your automobile radiator holds 1 kg of water, how many grams of ethylene glycol $[C_{2} H_{6} O_{2}]$ must you add to get the freezing point of the solution lowered to $- {2.8}^{0} C ?$

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answer is 93.

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Detailed Solution

$K_{f} \times \frac{w_{A} \times 1000}{m_{B} \times w_{A}} 2.8 = 18.6 \times \frac{w_{B} \times 1000}{62 \times 1000} w_{B} = 93 g$

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