K_H value for some gases at the same temperature 'T' are given,
Gas K_H/k bar
Ar 40.3
CO₂ 1.67
HCHO 1.83x10^-5
CH₄ 0.413
where K_H is Henry's Law constant in water. The order of their solubility in water is

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Ar<CO₂<CH₄<HCHO

Ar<CH₄<CO₂<HCHO

HCHO<CO₂<CH₄<Ar

HCHO<CH₄<CO₂<Ar

answer is A.

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Detailed Solution

Greater the value of K_H for a gas, lesser is its solubility in water. So, order of solubility of gases in water is
$Ar < {CO}_{2} < {CH}_{4} < HCHO .$

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