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Q.

Kinetic and potential energy ( in eV) of electron present in second Bohr’s orbit of hydrogen atom are respectively [Energy of first Bohr’s orbit =−13.6eV]

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a

−1.51,−3.02

b

3.02,−1.51

c

−13.6,−27.2

d

3.4,−6.8

answer is C.

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Detailed Solution

(KE)n=+13.6Z2n2eV/ atom 

 For n=2,(KE)=+3.4eV/ atom 

(PE)n=−27.2Z2n2eV/ atom 

 for n=2, PE=−6.8eV/ atom 

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