Kinetic energy of electron in a mono electronic species is +1312 kJ/mole. Then which of the following statements are correct
I) The electron is present in the $2^{n d}$ orbit of $H e^{+}$ ion

II) The electron is present in the $2^{n d}$ orbit of H atom

III) The electron is present in the $3^{r d}$ orbit of $L i^{+ 2}$ ion

IV) The electron is present in the $4^{t h}$ orbit of $H e^{+}$ ion

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III and IV

I and III

II and III

I and II

answer is C.

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Detailed Solution

$K . E = \frac{1312 \times z^{2}}{n^{2}} K J / m o l e$

$Hint \begin{matrix} z = n \end{matrix}$

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