KMnO4 in basic medium is reduced to

2KMnO7+2KOH→2K2MnO4+H2O+O2K2MnO4+2H2O→2MnO2+4KOH+2O--------------------2KMnO2+H2O alkaline ⟶2MnO2+2KOH+3[O]

KMnO4 in basic medium is reduced to

2KMnO7+2KOH→2K2MnO4+H2O+O2K2MnO4+2H2O→2MnO2+4KOH+2O--------------------2KMnO2+H2O alkaline ⟶2MnO2+2KOH+3[O]

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KMnO₄ in basic medium is reduced to

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K₂Mn₄

Mn(OH)₂

MnO₂

Mn²⁺

answer is C.

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Detailed Solution

$\begin{array}{l} 2 {KMnO}_{7} + 2 KOH \to 2 K_{2} {MnO}_{4} + H_{2} O + O \\ 2 K_{2} {MnO}_{4} + 2 H_{2} O \to 2 {MnO}_{2} + 4 KOH + 2 O \\ - - - - - - - - - - - - - - - - - - - - \\ 2 {KMnO}_{2} + H_{2} O alkaline ⟶ 2 {MnO}_{2} + 2 KOH + 3 [O] \end{array}$