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$K M n O_{4}$ is titrated with ferrous ammonium sulphate hexa hydrate in presence of dilute $H_{2} S O_{4} .$ Number of water molecules produced for 2 molecules of $K M n O_{4}$ is _____.

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answer is 68.

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Detailed Solution

$2 M n O_{4}^{-} + 10 F e^{+ 2} + 16 H^{+} \to$
$2 M n^{+ 2} + 10 F e^{+ 3} + 8 H_{2} O$
$∴ 10 (F e S O_{4} {(N H_{4})}_{2} S O_{4} .6 H_{2} O)$ has $H_{2} O$ 60 molecules
Total $H_{2} O$ moleculer = 60 + 8 = 68

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