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Q.

KMnO4  reacts with oxalic acid according to the equation 2MnO4−+5C2O4−2+16H+→2Mn+2+10CO2+8H2O . Here 20mL of 0.1M KMnO4 is equivalent to 

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a

120 ml of 0.25M  H2C2O4

b

150 ml of 0.10M  H2C2O4

c

25ml of 0.20M  H2C2O4

d

50ml of 0.20M  H2C2O4

answer is C.

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Detailed Solution

Equivalance of  KMnO4=20×0.1×5=10 
Eq. of oxalic acid  =25×0.2×2=10

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