${KMnO}_{4} + KI + H^{\oplus} \overset{Acidic Medium}{\to} X$
${KMnO}_{4} + KI + O H^{-} \overset{Neutral (or) Alkaline Medium}{\to} y$
Hence, x & y are_ & __respectively

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$I O_{4}^{-} & I_{2}$

$I_{2} & {IO}_{3}^{-}$

$I_{2} & {IO}_{4}^{-}$

${IO}_{3}^{-} & I_{2}$

answer is B.

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Detailed Solution

Acidic medium: Iodine is liberated from potassium iodide
10I^- + 2MnO₄^- + 16H⁺ → 2Mn²⁺ + 8H₂O + 5I₂
Alkaline medium: Iodide is oxidized to iodate
2MnO₄^- + H₂O + I^-→ 2MnO₂ + 2OH^- + IO₃^-

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