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Q.

$K_{p} / K_{c}$ for $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ (gaseous phase) at 400 K is

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a

$(400 R)^{2}$

b

$(400 {R^{)}}^{- 2}$

c

$(127)^{- 2}$

d

$400 R$

answer is C.

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Detailed Solution

$K_{p} = K_{c} (R T)^{Δ n}$

$Δ n = n_{p} - n_{r}$ = no. of moles of product & nr = no. of moles of reactant

For reaction: $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$

$Δ n = 2 - (1 + 3) = 2 - 4 = - 2$

$K_{p} = K_{c} (R 400)^{- 2} = K_{p} / K_{c} = (400 R)^{- 2}$

Hence, the correct option is C i.e., $(400 R)^{- 2}$ .

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