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Q.

Ksp of AgCl is 1010M2 Electrode potential of Ag/AgCl electrode in contact with 1M KCl at 25C is EAg+/Ag0=+0.8V

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a

1.08V

b

0.592

c

0.8V

d

0.20V

answer is D.

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Detailed Solution

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[Ag+] =Ksp[Cl-]=10-101=10-10

Ag++e-Ag

ERP=ERP0-0.0591nlog1[Ag+]

ERP=ERP0-0.0591nlog110-10

ERP=0.8-0.0591×10=0.2090.2

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