${\mathrm{K}}_{\mathrm{sp}} \mathrm{of} \mathrm{AgCl}=1.0\times {10}^{-10}\text{. Select the incorrect statement(s). }$

$\left[{\mathrm{Ag}}^{+}\right]\left[{\mathrm{Cl}}^{-}\right]=K_{\mathrm{sp}}=1\times {10}^{-10}$
 

$\therefore {\mathrm{p}}_{\mathrm{Aq}}+{\mathrm{p}}_{\mathrm{Cl}}=10$
Hence, (a) is true.
$\text{ In }0.01 \mathrm{M} {\mathrm{Ag}}^{+}, \left[{\mathrm{Cl}}^{-}\right]=\frac{1\times {10}^{-10}}{0.01}=1\times {10}^{-8}$
$\therefore {\mathrm{p}}_{\mathrm{Cl}}=8$
Hence, (b) is true.
$\text{ In all cases }{\mathrm{p}}_{\mathrm{Aq}}+{\mathrm{p}}_{\mathrm{Cl}}=10\text{ for }\mathrm{AgCl}\text{ at a given temperature. }$
Thus, (c) is incorrect.
$\mathrm{Since}, \left[{\mathrm{Ag}}^{+}\right]=\left[{\mathrm{Cl}}^{-}\right]$
$$\begin{gathered} \therefore \left[{\mathrm{Ag}}^{+}\right]=\left[{\mathrm{Cl}}^{-}\right]=\sqrt{{\mathrm{K}}_{\mathrm{sp}}}={10}^{-5}\mathrm{M} \\ \log \left[{\mathrm{Ag}}^{+}\right]=\log \left[{\mathrm{Cl}}^{-}\right]=-5 \\ -\log \left[{\mathrm{Ag}}^{+}\right]=-\log \left[{\mathrm{Cl}}^{-}\right]=5 \\ {\mathrm{p}}_{\mathrm{Ag}}={\mathrm{p}}_{\mathrm{Cl}}=5 \end{gathered}$$
Hence, (d) is also true.