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Q.

$K_{w}$ value of water is $10^{- 13} M^{2}$ at certain temperature. The sum of $p H a n d p O H$ for a neutral aqueous solution at this temperature is

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a

$13.30$

b

$14$

c

$13$

d

$7.0$

answer is D.

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Detailed Solution

$p H + p O H = p K_{w} p K_{w} = - \log [K_{w}] p K_{w} = - \log [10^{- 13}] p K_{w} = 13 p H + p O H = 13$

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