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Q.

L 1, 3, L1 1, -1 are ends of latusrectum of a parabola, then area of quadrilaterial formed by tangents and normals at L and L1 IS

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a

2

b

8

c

16

d

4

answer is C.

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Detailed Solution

Given L=(1,3),L'=(1,-1) Now LL1=4 ⇒4a=4   ⇒a=1

Quadrilaterial is the square of side 8a

Required area=8a2=8

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