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$L (1, 3), L^{1} (1, - 1)$ are ends of latusrectum of a parabola, then area of quadrilaterial formed by tangents and normals at L and L¹ IS

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Detailed Solution

$G i v e n L = (1, 3), L' = (1, - 1) N o w {LL}^{1} = 4 \Rightarrow 4 a = 4 \Rightarrow a = 1$

Quadrilaterial is the square of side $\sqrt{8} a$

$R e q u i r e d a r e a = 8 a^{2} = 8$

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