Lattice energy of NaCl is 'X'. If the ionic size of A+2 is equal to that of Na+ and B–2 is equal to Cl–, then lattice energy associated with the crystal AB is

Lattice energy Given ionic size of Na+ = A+2Given ionic size of Cl- = B-2thus inter ionic distance remains constant

Lattice energy of NaCl is 'X'. If the ionic size of A+2 is equal to that of Na+ and B–2 is equal to Cl–, then lattice energy associated with the crystal AB is

Lattice energy Given ionic size of Na+ = A+2Given ionic size of Cl- = B-2thus inter ionic distance remains constant

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Lattice energy of NaCl is 'X'. If the ionic size of A⁺² is equal to that of Na⁺ and B^–2 is equal to Cl^–, then lattice energy associated with the crystal AB is

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Lattice energy $\large U\propto \frac{{{Z}^{+}}{{Z}^{-}}}{{{r}_{+}}+{{r}_{-}}}$

Given ionic size of Na⁺ = A⁺²

Given ionic size of Cl^- = B^-2

thus inter ionic distance $\large \left( {{r}_{+}}+{{r}_{-}} \right)$ remains constant

$\large \therefore U\propto {{Z}^{+}}{{Z}^{-}}$

$\large \Rightarrow \frac{{{U}_{NaCl}}}{{{U}_{AB}}}=\frac{\left( 1 \right)\left( 1 \right)}{\left( 2 \right)\left( 2 \right)}$

$\large {{U}_{AB}}=4{{U}_{NaCl}}$

$\large {{U}_{AB}}=4X\left( X={{U}_{NaCl}} \right)$

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Lattice energy of NaCl is 'X'. If the ionic size of A+2 is equal to that of Na+ and B–2 is equal to Cl–, then lattice energy associated with the crystal AB is

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Lattice energy of NaCl is 'X'. If the ionic size of A⁺² is equal to that of Na⁺ and B^–2 is equal to Cl^–, then lattice energy associated with the crystal AB is