Leaching of gold with dilute aqueous solution of NaCN in presence of oxygen gives complex [A],
which on reaction with zinc forms the elemental gold and another complex [B]. [A] and [B], respectively are :-

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${[Au (CN)_{2}]}^{-} and {[Zn (CN)_{4}]}^{2 -}$

${[Au (CN)_{4}]}^{-} and {[Zn (CN)_{2} (OH)_{2}]}^{2 -}$

${[Au (CN)_{2}]}^{-} and {[Zn (OH)_{4}]}^{2 -}$

${[Au (CN)_{4}]}^{2 -} and {[Zn (CN)_{6}]}^{4 -}$

answer is C.

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Detailed Solution

$\begin{aligned} Au + NaCN \to Na [Au (CN)_{2}] \\ Zn + Na [Au (CN)_{2}] \to {Na}_{2} [Zn (CN)_{4}] + Au \end{aligned}$

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