lead(II) fluoride $({PbF}_{2})$ lead {II) chloride $({PbCl}_{2})$ lead(II) bromide $({PbBr}_{2})$ and lead(II) iodide $({PbI}_{2})$ are all slightly soluble in water. Which lead salt will increase in solubility when its saturated solution is acidified?

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${PbBr}_{2}$

${PbI}_{2}$

${PbCl}_{2}$

${PbF}_{2}$

answer is A.

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Detailed Solution

$F^{-}$ is a strong conjugate base and hence, gets removed in acidic medium, thus increasing solubility.

Thus, ${PbF}_{2}$ will increase in solubility when its saturated solution is acidified.

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