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Q.

Length of chord of parabola y2=4ax whose equation is y-2x+42a=0

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a

211a 

b

42a 

c

82a 

d

63a

answer is D.

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Detailed Solution

Given y2=4ax -(1) and  y=2x-42a      -(2)

solving (1) & (2)

   2x-42 a2=4ax 2x2+32a2-16ax-4ax=0     2x2-20ax+32a2=0      x2-10ax+16a2=0

difference  of roots x1-x2=100a2-64a2                =6a

Length of the Chord =x1-x2 1+m2

                                     =(6a) 3=63 a 

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