Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Length of the DNA is 510 angstroms. Find the percentage of cytosine. Assume the number of adenine bases is 30 in that DNA.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

10%

b

40%

c

30%

d

20%

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Pitch of the DNA is 34 angstroms.
Number of turns in the DNA= 510/34= 15 turns
No. of base pairs per turn = 10bp
No. of base pairs in 15 turns- 15 X10= 150bp
No. of adenine = 30= No. of thymine
Total no. of (A+T) = 30+30= 60
Total no. G+C= 300-60= 240
No. of C= 240/2=120
% C= (120/300) X 100= 40%.

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon