Length of the double ordinate of the parabola ${\displaystyle y^2=4x}$, at a distance of 16 units from its vertex is

As we know that,

Given to us, $y^2=4x$

Comaparing with $y^2=4ax$

Therefore We Get, $4a=4$ $\Rightarrow a=1$

Length Of Latus Rectum$=4a$

Length Of Latus Rectum$=4\left(1\right)$$=4$

$$\begin{gathered} \Rightarrow a{t}^2=16 \\ \Rightarrow \left(1\right)t^2=16 \\ \Rightarrow t=\pm 4 \end{gathered}$$

Therefore Length Of Double Ordinate $=4at$

Length Of Double Ordinate$$\begin{gathered} =4\times 1\times 4 \\ =16 \end{gathered}$$

Therefore Final Answer Is 16.