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Q.

Let 3π4<θ<π  and 2cotθ+1sin2θ=kcotθ  then k is equal to

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a

1

b

–1

c

0

d

12

answer is B.

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Detailed Solution

G.E=2cotθ+(1+cot2θ)

=(1+cotθ) , (since 3π4<θ<π cotθ<1,(1+cotθ<0) )

=1cotθ , k=1

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