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Q.

Let the sequence a1,a2,a3.........  form an A.P. Then a12a22+a32a42+........+a2n12a2n2=

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a

n2n1(a12a2n2)

b

None of these

c

nn+1(a12+a2n2)

d

2nn1(a2n2a12)

answer is A.

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Detailed Solution

a12a22+a32a42+........+a2n12a2n2

=(a1a2)(a1+a2)+(a3a4)(a3+a4)+.............+(a2n1a2n)(a2n1+a2n)

=d[a1+a2+...+a2n]

=d2n2[a1+a2n]

=dn[a12a2n2]a1a2n=nd(a12a2n2)(2n1)d

=n2n1(a12a2n2)

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