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Q.

Let ⨍ :(-1,1)→R  be a differentiable function with ⨍ (0)=-1 and ⨍ 1(0). Let g(x)=⨍ (2⨍ (x)+2)2 then g1(0)

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a

-4

b

-2

c

0

d

4

answer is D.

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Detailed Solution

g(x)=f2fx+22 g1(x)=2f2fx+2·f1(2f(x)+2) g1(0)=4f(0)·f1(0)·f1(0)          =4(-1)(1)2          =-4

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