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Q.

Let  5x2+4xy+y2=1 & z2=x2+y2,x>y>0. Which of the following is/are INCORRECT?

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a

Minimum value of z is 21

b

Maximum value of z is  21

c

Minimum value of z is 12

d

Maximum value of z is  1

answer is A, B, C, D.

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Detailed Solution

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Let   x=rcosθ&y=rsinθ,0<θ<π4 , then z=r and
 5r2cos2θ+4r2sinθcosθ+r2sin2θr2=12cos2θ+2sin2θ+3
 rdrdθ=2sin2θcos2θ(2cos2θ+2sin2θ+3)2
Now r is increasing if  sin2θ>cos2θtan2θ>1π8<θ<π4.
And r is decreasing if  sin2θ<cos2θtan2θ<10<θ<π8.
Now for  θ=π8,r2=13+22  i.e. (322)  hence  r=21.

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