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Q.

 Let A=210121012. If |adj(adj(adj2A))|=(16)n, then ' n ' is equal to 

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a

8

b

12

c

10

d

9

answer is C.

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Detailed Solution

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|A|=2(3)1(2)=4|adj(adj(adj(2A)))| |2A|(n1)3 =∣2A|8=22448 =246424=1610 n=10

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 Let A=21012−10−12. If |adj⁡(adj⁡(adj⁡2A))|=(16)n, then ' n ' is equal to