Let a→=2i+3j→+k→,b→=4i¯+j→,c→=i¯−3j→−7k→, If r→=xi¯+yj→+zk→,r→.a→=9;r→.b→=7,r→.c→=6. Then (x,y,z)=

r→=xi→+yj→−zk→r→⋅a→=9,r→⋅b→=7,r→⋅c→=6We get (x,y,z)=(1,3,−2)

Let a→=2i+3j→+k→,b→=4i¯+j→,c→=i¯−3j→−7k→, If r→=xi¯+yj→+zk→,r→.a→=9;r→.b→=7,r→.c→=6. Then (x,y,z)=

r→=xi→+yj→−zk→r→⋅a→=9,r→⋅b→=7,r→⋅c→=6We get (x,y,z)=(1,3,−2)

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Let $\vec{a} = 2 i + 3 \vec{j} + \vec{k}, \vec{b} = 4 \bar{i} + \vec{j}, \vec{c} = \bar{i} - 3 \vec{j} - 7 \vec{k}$ , If $\vec{r} = x \bar{i} + y \vec{j} + z \vec{k},$ $\vec{r} . \vec{a} = 9; \vec{r} . \vec{b} = 7, \vec{r} . \vec{c} = 6$ . Then $(x, y, z) =$

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$(1, - 3, 2)$

$(- 1, 3, - 2)$

$(1, 3, 2)$

$(1, 3, - 2)$

answer is D.

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$\begin{array}{l} \vec{r} = x \vec{i} + y \vec{j} - z \vec{k} \\ \vec{r} \cdot \vec{a} = 9, \vec{r} \cdot \vec{b} = 7, \vec{r} \cdot \vec{c} = 6 \end{array}$
We get $(x, y, z) = (1, 3, - 2)$

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Let a→=2i+3j→+k→,b→=4i¯+j→,c→=i¯−3j→−7k→, If r→=xi¯+yj→+zk→,r→.a→=9;r→.b→=7,r→.c→=6. Then (x,y,z)=

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Let $\vec{a} = 2 i + 3 \vec{j} + \vec{k}, \vec{b} = 4 \bar{i} + \vec{j}, \vec{c} = \bar{i} - 3 \vec{j} - 7 \vec{k}$ , If $\vec{r} = x \bar{i} + y \vec{j} + z \vec{k},$ $\vec{r} . \vec{a} = 9; \vec{r} . \vec{b} = 7, \vec{r} . \vec{c} = 6$ . Then $(x, y, z) =$