Let $\mathrm{A}=\left[\begin{array}{ccc}\mathrm{a}& 3& 5\\ 5& -1& 3\\ 2& 3& -4\end{array}\right]$ and $\mathrm{B}=\left[\begin{array}{ccc}\mathrm{b}& 1& 4\\ 4& \mathrm{c}& 1\\ -3& 1& \mathrm{d}\end{array}\right]\text{;}$  If the trace of A is -4 and   $\mathrm{AB}=\left[\begin{array}{ccc}-1& 0& 17\\ -3& 10& 25\\ 28& -8& 3\end{array}\right]$, then a + b + c + d =

$AB=\left[\begin{array}{ccc}\mathrm{a}& 3& 5\\ 5& -1& 3\\ 2& 3& -4\end{array}\right]\left[\begin{array}{ccc}\mathrm{b}& 1& 4\\ 4& \mathrm{c}& 1\\ -3& 1& \mathrm{d}\end{array}\right]$=$\left[\begin{array}{ccc}-1& 0& 17\\ -3& 10& 25\\ 28& -8& 3\end{array}\right]$

$\left[\begin{array}{ccc}ab-3& a+3c+5& 4a+3+5d\\ 5b-13& 8-c& 19+3d\\ 2b+24& 3c-2& 11-4d\end{array}\right]=\left[\begin{array}{ccc}-1& 0& 17\\ -3& 10& 25\\ 28& -8& 3\end{array}\right]$

a = 1, b = 2, c = -2, d = 2