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Q.

Let A and B are non singular square matrices of order  3×3  such that B is adjoint of A and A1AT=|A|B1. Match List-I with List-II and select the correct answer using the code given below the list .

 LIST-I LIST-II
A)|A|  is equal toP)1
B)|B| is equal toQ)A= I
C)If A is symmetric matrix thenR)A3 = I
D)If A is orthogonal matrix thenS)B = I
  T)B3 = I
  U)-1

Where  |X| denotes determinant of matrix X and I is identity matrix.

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a

AP, BU, CQ,S, DR,T

b

AU, BU, CS,T, DQ,R

c

AU, BU, CQ,R, DS,T

d

AP, BP, CQ,R,S,T, DR,T

answer is D.

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Detailed Solution

 A1AT=|A|B1,B=adj.A
taking determinant,
|A1|.|AT|=|A|3.|B1| |A3|.1|B|=1 |A|3|A|2=1|A|=1|B|=1
Now,  A1AT=B1
If A is symmetric
A1A=B1B=I adjA=IA=I
If A is orthogonal then  AT=A1
A1A1=B1B=A2 adjA=A2 A  adj  A=A3 A3=|A|I A3=I(adjA)3.A3=B3 B3=I

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