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Q.

Let a, b and c be three unit vectors such that a+b+c=0. If a¯.b¯+b¯.c¯+c¯.a¯ and d=a¯×b¯+b¯×c¯+c¯±a¯ then the ordered pair, λ, d is equal to :

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a

32, 3b×c

b

-32, 3c×b

c

-32, 3a×b

d

32, 3a×c

answer is D.

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Detailed Solution

a¯=b¯=c¯=1a¯+b¯+c¯=O¯  a¯+b¯+c¯2=0 1+1+1+2(a¯.b¯+b¯.c¯+c¯.a¯)=0 3+2λ=0 λ=-32a¯+b¯+c¯=o¯ a¯×b¯=b¯×c¯=c¯×a¯d=a¯×b¯+b¯×c¯+c¯×a¯=3(a¯×b¯)=3(b¯×c¯)                                                         =3(c¯×a¯)

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