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Q.

Let a, b, c and d be positive real numbers such that a+b+c+d=11. If the maximum value of a5b3c2d is 3750 β, then the value of β is

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a

90

b

110

c

108

d

55

answer is B.

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Detailed Solution

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5(a5)+3(b3)+2(c2)+d11((a5)5(b3)3(c2)2d)111
a5b3c2d55×33×22 =3750×90β=90

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