Let a, b, c, d be real numbers in G.P. If  u, v, w satisfy the system of equations  $u+2v+3w=6,4u+5v+6w=12,6u+9v=4$ 

 If the roots of the equation  $20x^2+10{(a-d)}^{2}x-9=0$  are  $x_1,x_2$ such that  $\left|x_1\right|<\left|x_2\right|$ and  the roots of the equation  $(\frac{1}{\text{u}}+\frac{1}{\text{v}}+\frac{1}{\text{w}}){\text{x}}^2+[{(\text{b}-\text{c})}^2+{(\text{c}-\text{a})}^2+{(\text{d}-\text{b})}^2]\text{x}+\text{u}+\text{v}+\text{w}=0$  are $x_3,x_4$ such that  $\left|x_3\right|<\left|x_4\right|$, then the value of  $\left|x_1\right|\times \left|x_4\right|+\left|x_2\right|\times \left|x_3\right|$, is equal to ……