Let (a¯,b¯)denote the angle between vectors a¯ and b¯. If a¯=2i¯+3j¯+6k¯,a⋅¯b¯=4 and (a¯,b¯)=cos−1⁡421 then a¯+b¯=

a¯=2i¯+3j¯+6k¯,a⋅¯b¯=4 and (a¯,b¯)=cos−1⁡421by properties of dot producta¯+b¯=i¯+j¯+8k¯

Let (a¯,b¯)denote the angle between vectors a¯ and b¯. If a¯=2i¯+3j¯+6k¯,a⋅¯b¯=4 and (a¯,b¯)=cos−1⁡421 then a¯+b¯=

a¯=2i¯+3j¯+6k¯,a⋅¯b¯=4 and (a¯,b¯)=cos−1⁡421by properties of dot producta¯+b¯=i¯+j¯+8k¯

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Let $(\bar{a}, \bar{b})$ denote the angle between vectors $\bar{a} and \bar{b}$ . If $\bar{a} = 2 \bar{i} + 3 \bar{j} + 6 \bar{k}, \bar{a \cdot} \bar{b} = 4$ and $(\bar{a}, \bar{b}) = \cos^{- 1} (\frac{4}{21})$ then $\bar{a} + \bar{b} =$

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$\bar{i} + \bar{j} + 8 \bar{k}$

$3 \bar{i} + 5 \bar{j} + 8 \bar{k}$

$3 \bar{i} + \bar{j} + 8 \bar{k}$

$3 \bar{i} + 5 \bar{j} + 4 \bar{k}$

answer is D.

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$\bar{a} = 2 \bar{i} + 3 \bar{j} + 6 \bar{k}, \bar{a \cdot} \bar{b} = 4$ and $(\bar{a}, \bar{b}) = \cos^{- 1} (\frac{4}{21})$

by properties of dot product

$\bar{a} + \bar{b} =$ $\bar{i} + \bar{j} + 8 \bar{k}$

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Let (a¯,b¯)denote the angle between vectors a¯ and b¯. If a¯=2i¯+3j¯+6k¯,a⋅¯b¯=4 and (a¯,b¯)=cos−1⁡421 then a¯+b¯=

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Let $(\bar{a}, \bar{b})$ denote the angle between vectors $\bar{a} and \bar{b}$ . If $\bar{a} = 2 \bar{i} + 3 \bar{j} + 6 \bar{k}, \bar{a \cdot} \bar{b} = 4$ and $(\bar{a}, \bar{b}) = \cos^{- 1} (\frac{4}{21})$ then $\bar{a} + \bar{b} =$