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Q.

Let A be the set of first 10 natural numbers an R={(x,y)/xA,yN  and  x+2y=10} then n{dom(R1)}=

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a

4

b

3

c

5

d

6

answer is A.

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Detailed Solution

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R={(2,4),(4,3),(6,2),(8,1)}

The domain of inverse relation is 1,2,3,4

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Let A be the set of first 10 natural numbers an R={(x,y)/x∈A, y∈N  and  x+2y=10} then n{dom(R−1)}=