Let a circle be inscribed in the quadrant of a circle of diameter 4 then
Statement-I: The radius of inscribed circle is the positive root of the equation $r^{2} + 4 r - 4 = 0$
Statement-II: Distance between their centers = 2 (radius of circle inscribed)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

Statement-I is true, Statement-II is false.

Statement-I is true, Statement-II is true, statement-II is not the correct explanation of Statement-I

Statement-I is true, Statement-II is true, Statement-II is the correct explanation of Statement-I

Statement-I is false, Statement-II is true.

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$C_{1} C_{2} = \sqrt{2} r 2 - r = \sqrt{2} r \Rightarrow r^{2} + 4 r - 4 = 0$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE