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Q.

Let a force F be acting on a body free to rotate about a point 0 and let \mathbf{r} the position vector of any point P on the line of action of the force. The torque (τ) of this force about point O is defined as

τ=r×F

Given, F=(2i^+3j^-k^) N and r=(i^-j^+6k^) m

Find the torque of this force.

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a

(17i^+13j^+5k^)N-m

b

(-17i^+13j^+10k^)N-m

c

(-17i^+12j^+5k^)N-m

d

(-17i^+13j^+5k^)N-m

answer is D.

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Detailed Solution

τ=r×F=i^j^k^1-1623-1

=i^(1-18)+j^(12+1)+k^(3+2)

τ=(-17i^+13j^+5k^)N-m

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