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Q.

Let a function  f:NN be defined by fn=2n             ; n=2,4,6,8,...n-1          ;n=3,7,11,15,...n+12         ;n=1,5,9,13,...  then f is

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a

Onto but not one-one

b

One-one but not onto

c

Neither one-one nor onto

d

One-one and onto

answer is D.

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Detailed Solution

Given function is  fn=2n             ; n=2,4,6,8,...n-1          ;n=3,7,11,15,...n+12         ;n=1,5,9,...


When n = 2, 4, 6 then 2n Is the multiple of 4
When n = 3, 7, 11, 15 then (n-1) is not multiple of 4
When n=1, 5,9,13, then  (n+12) is the odd number
Every number gives exactly one value
Thus, f is one-one & onto
 

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