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Q.

Let a¯=i¯+2j¯, b¯=2j¯k¯  . If  r¯×a¯=b¯×a¯, r¯×b¯=a¯×b¯ ,then r¯|r¯|=  

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a

118(i¯+4j¯k¯)

b

118(i¯4j¯+k¯)

c

13(i¯j¯+k¯)

d

13(i¯+j¯k¯)

answer is A.

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Detailed Solution

r¯×a¯=b¯×a¯r¯×(a¯+b¯)=0r¯=λ(a¯+b¯)

r¯|r¯|=a¯+b¯|a¯+b¯|=i¯+4j¯k¯18

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