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Q.

Let a¯=i^+2j^k^ and b¯=i^+j^+k^ , p¯ is a unit vector such that [a¯  b¯p¯] is maximum. Then p¯ =

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a

16(i^2j^+k^)

b

13(i^+j^k^)

c

114(3i^2j^k^)

d

114(i^+2j^+3k^)

answer is C.

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Detailed Solution

a×b=i        j         k1      2     11        1         1=3j2jk

[abP]=P.(a×b)=P(3i2jk)[abP]=|P||a×b|cosθ[abP]ismaximamP=a×b|a×b|P=114(3i2jk)

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