Let a¯=j¯−k¯ and c¯=i¯−j¯−k¯, then the vector b¯ satisfying a¯ × b¯+c¯=0¯ and a¯ . b¯=3 is

Let b¯ = x, y, z & a¯ × b¯ = −c¯ ⇒ x=−1, y=1, z=−2∴ b¯ = −i¯+j¯−2k¯

Let a¯=j¯−k¯ and c¯=i¯−j¯−k¯, then the vector b¯ satisfying a¯ × b¯+c¯=0¯ and a¯ . b¯=3 is

Let b¯ = x, y, z & a¯ × b¯ = −c¯ ⇒ x=−1, y=1, z=−2∴ b¯ = −i¯+j¯−2k¯

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Let $\bar{a} = \bar{j} - \bar{k}$ and $\bar{c} = \bar{i} - \bar{j} - \bar{k}$ , then the vector $\bar{b}$ satisfying $(\bar{a} \times \bar{b}) + \bar{c} = \bar{0}$ and $\bar{a} . \bar{b} = 3$ is

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$\bar{i} + \bar{j} - 2 \bar{k}$

$\bar{i} - \bar{j} - 2 \bar{k}$

$2 \bar{i} - \bar{j} + 2 \bar{k}$

$- \bar{i} + \bar{j} - 2 \bar{k}$

answer is D.

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Let $\bar{b} = (x, y, z) & \bar{a} \times \bar{b} = - \bar{c} \Rightarrow x = - 1, y = 1, z = - 2$

$∴ \bar{b} = - \bar{i} + \bar{j} - 2 \bar{k}$

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Let a¯=j¯−k¯ and c¯=i¯−j¯−k¯, then the vector b¯ satisfying a¯ × b¯+c¯=0¯ and a¯ . b¯=3 is

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Let $\bar{a} = \bar{j} - \bar{k}$ and $\bar{c} = \bar{i} - \bar{j} - \bar{k}$ , then the vector $\bar{b}$ satisfying $(\bar{a} \times \bar{b}) + \bar{c} = \bar{0}$ and $\bar{a} . \bar{b} = 3$ is