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Let a light beam of total intensity $1 μ W {cm}^{- 2}$ falls on a clean iron sample piece with J work function 4.5 eV and of 1.0 cm² area. Assume that iron sample reflects 96% of light and that only 3% ofthe absorbed energy lies in the violet region which can cause photoemission (of wavelength 250 nm). Number of electrons emitted will be

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$3.0 \times 10^{9} electrons per second$

$1.5 \times 10^{10} electrons per second$

$3.0 \times 10^{10} electrons per second$

$1.5 \times 10^{9} electrons per second$

answer is D.

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Detailed Solution

Only 4% of energy is absorbed and only 3% of this can cause photo emission, part of intensity available for photoemission is

$I^{'} = 0.03 \times 0.04 I_{0} = 1.2 nW {cm}^{- 2}$

$∴$ Number of electrons/second

$= \frac{1.2 \times 10^{- 9} W}{h f} = 1.5 \times 10^{9} electrons per second$

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