Let $A=\{n\in N;HCF(n,45)=1\}$ and let  $B=\{2k:K\in \{1,2,3,\mathrm{....},100\left\}\right\}$ then the sum of all the elements of  $A\cap B$ is $\lambda$ then sum of digits of  $\lambda$ is

$\begin{array}{l}B=\{2,4,6,\mathrm{....200}\}\\ 45=3^2\times 5\end{array}$

Elements of set A should not multiples of 3 and 5
Set of multiples of 2 and 3,  $A_6=\{6,12,18,\mathrm{...198}\}$
Set of multiples   2 and 5 ;  $A_{10}=\{10,20,30,\mathrm{......},200\}$
Set of multiples of 2,3 and 5 is  $A_{30}=\{30,60,\mathrm{....},180\}$

Sum =